x^2+4x-999=0

Solution for x^2+4x-999=0 equation:

x^2+4x-999=0

a = 1; b = 4; c = -999;
Δ = b2-4ac
Δ = 42-4·1·(-999)
Δ = 4012
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4012}=\sqrt{4*1003}=\sqrt{4}*\sqrt{1003}=2\sqrt{1003}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{1003}}{2*1}=\frac{-4-2\sqrt{1003}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{1003}}{2*1}=\frac{-4+2\sqrt{1003}}{2}
$